SOLUTION: You invested ​$29,000 in two accounts paying 6% and 8% annual​ interest, respectively. If the total interest earned for the year was $ 2300,how much was invested at each​ rat

Algebra.Com
Question 1165278: You invested ​$29,000 in two accounts paying 6% and 8% annual​ interest, respectively. If the total interest earned for the year was $ 2300,how much was invested at each​ rate?
Answer by Seutip(231)   (Show Source): You can put this solution on YOUR website!
Let x be the amount invested at 6%
y be the amount invested at 8%
Equations:
x+y=29,000
0.06x+0.08y=2300
So, x=29,000-y the substitue
0.06(29,000-y)+0.08y=2300
1740-0.06y+0.08y=2300
0.02y=560
y=28,000
x=1,000
You invested $1000 in 6% and $28000 in 8%
Hope that helps!

RELATED QUESTIONS

You invested $7000 in two accounts paying 8% and 6% annual interest, respectively. If the (answered by jorel1380)
You invested $12,000 in two accounts paying 6% and 8% annual interest, respectively. If... (answered by mananth,richwmiller)
you invested $29,000 in two accounts paying 3% and 8% annual interest, respectively. If... (answered by stanbon)
You invested $8000 in two accounts paying 3% and 8% annual interest, respectively. If the (answered by mananth)
you invested $29,000 in two accounts paying 8% and 9% annual interest respectively. if... (answered by Maths68)
You invested $7000 in two accounts paying 7% and 8% annual interest, respectively. If the (answered by Algebraic)
You invested $7000 in two accounts paying 7% and 8% annual interest, respectively. If the (answered by mananth)
you invested $14000 in two accounts paying 3% and 8% annual interest respectively. If the (answered by ewatrrr)
You invested 14,000 in two accounts paying 6% and 9% annual interest, respectively. If... (answered by rfer)
You invested ​$29,000 in two accounts paying 6% and 9% annual​ interest,... (answered by josgarithmetic,MathTherapy)