SOLUTION: How do I find the formula for an exponential function that passes through the two given points?
(0,6) and (3,750)
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-> SOLUTION: How do I find the formula for an exponential function that passes through the two given points?
(0,6) and (3,750)
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Question 1137506: How do I find the formula for an exponential function that passes through the two given points?
(0,6) and (3,750) Found 3 solutions by MathLover1, jim_thompson5910, greenestamps:Answer by MathLover1(20850) (Show Source):
You can put this solution on YOUR website! original exponential formula is
use given points (,) and (,), set up system and solve for and
You can put this solution on YOUR website!
The general template for an exponential function is
where 'a' and 'b' are fixed values (constants).
The first point given to us is (0,6) meaning that x = 0 and y = 6 pair up together. Let's plug them both into the template to see what happens
replace x with 0; replace y with 6
anything to the zeroth power is equal to 1
one times any number is itself
So we have one of the constants we need.
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Now plug in the other point (x,y) = (3,750). Also we will plug in a = 6 that we found earlier. Then solve for b
replace 'a' with 6
plug in (x,y) = (3,750)
Divide both sides by 6
Apply the cube root to both sides. You can also think of it as raising both sides to the 1/3 power.
We found the other constant
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Therefore,
a = 6
b = 5
Making the function be which is the same as since y = f(x).
As a check, plug in x = 0 to get
So we get the proper output for the input x = 0. Repeat for the input x = 3 as well
that output is correct as well. The function is confirmed. Both points are on the graph of this function curve.