# SOLUTION: decompose into a partial fraction 3x^2+15x+8/(x+1)(x+2)(x-3)

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 Question 113750: decompose into a partial fraction 3x^2+15x+8/(x+1)(x+2)(x-3)Answer by stanbon(57978)   (Show Source): You can put this solution on YOUR website!decompose into a partial fraction 3x^2+15x+8/(x+1)(x+2)(x-3) --------------- 3x^2+15x+8/(x+1)(x+2)(x-3) = A/(x+1) + B/(x+2) + C/(x-3) = A(x+2)(x-3) + B(x+1)(x-3) + C(x+1)(x+2 / ...... = A(x^2-x-6) + B(x^2-2x-3) + C(x^2+3x+2)/ .... ------------------ A+B+C = 3 -A-2B+3C = 15 -6A-3B+2C = 8 ------------------- Using the Matrix function of a TI-83 I get: A = 1 B = -2 C = 4 =========== Cheers, Stan H.