SOLUTION: Using long division, find the quotient and remainder (if any). 3x^4-4x^2+4x+8/ x+1

Question 1137499: Using long division, find the quotient and remainder (if any).
3x^4-4x^2+4x+8/ x+1
Found 2 solutions by josgarithmetic, MathLover1:
Answer by josgarithmetic(39628) (Show Source): You can put this solution on YOUR website!

First ask, what is ? That is . After that you do what you normally do in long division... 3x^3 _________________________________________ x+1 | 3x^4 0x^3 -4x^2 4x 8 | | 3x^3 -3x^2 -x 5 _________________________________________ x+1 | 3x^4 0x^3 -4x^2 4x 8 | | 3x^4 3x^3 --------------- 0 -3x^3 -4x^2 -3x^3 -3x^2 -------------- 0 -x^2 4x -x^2 -x ---------- 5x 8 5x 5 ----------- 3

Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

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