SOLUTION: Can someone help with this. the resistance in a cable conducting electricity varies directly as the length of the cable and inversely as the square of the diameter of the cable

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Question 1109083: Can someone help with this.
the resistance in a cable conducting electricity varies directly as the length of the cable and inversely as the square of the diameter of the cable. If a cable 8 feet long with a 1-inch diameter has a resistance of 8 ohms, what is the resistance in a cable 20 ft with a diamter of .5 inches

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
the resistance in a cable conducting electricity varies directly as the length of the cable and inversely as the square of the diameter of the cable. If a cable 8 feet long with a 1-inch diameter has a resistance of 8 ohms, what is the resistance in a cable 20 ft with a diameter of .5 inches
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R = k*L/d^2
Solve for "k"::
8 = k*8/1^2
k = 64
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R = 64*L/d^2
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R = 64*20/(0.5)^2 = 64*20/(1/4) = 64*80 = 5120 ohms
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Cheers,
Stan H.
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