SOLUTION: f(x) = { 2x + 1, x < 0; 2x + 2, x ≥ 0
f(t^2+1)
Algebra.Com
Question 1090039: f(x) = { 2x + 1, x < 0; 2x + 2, x ≥ 0
f(t^2+1)
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Since is always greater than zero,
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