SOLUTION: Consider the functions \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}.\]Explain why $f$ and $g$ are not the same function

Algebra.Com
Question 1088256: Consider the functions
\[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}.\]Explain why $f$ and $g$ are not the same function.

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

.....to find out what the domain and range are

{ element : or }
range:
{ : or }



domain:
{ element : }
range:
{ element : }
so, and are not same because they have different domain and range

RELATED QUESTIONS

The functions $f$ and $g$ are defined as follows: \[f(x) =... (answered by ikleyn)
Consider the functions f and g defined by f(x)=sqrt((x+1)/(x-1)) and... (answered by ikleyn)
Consider the functions f(x) = sqrt((x+1)/(x-1)) and g(x) = sqrt(x+1)/sqrt(x-1) Explain... (answered by Theo)
−2x+15y=−24space, minus, 2, x, plus, 15, y, equals, minus, 24 \qquad... (answered by ikleyn,fractalier)
The functions f and g are defined as follows: f(x) = sqrt(x+1/x-1) g(x) =... (answered by ikleyn)
Consider two functions, f and g, given by: {{{ f(x)= sqrt ( x-1 ) }}} and {{{ g(x)= sqrt... (answered by jim_thompson5910,CharlesG2)
The functions f and g are defined as follows: f(x) = sqrt(x+1/x-1) and g(x) =... (answered by ikleyn,greenestamps)
Consider f(x) = sqrt(4x^2 + 1 ) and g(x) = x + 3 /x^2 . Find the composite functions f... (answered by solver91311)
Find the domain of these functions. f(x)=7-x^2 g(x)=2x+1/x-1 f(x)=sqrt(x-5)... (answered by solver91311)