SOLUTION: Consider the functions
\[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}.\]Explain why $f$ and $g$ are not the same function
Algebra.Com
Question 1088256:  Consider the functions
\[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}.\]Explain why $f$ and $g$ are not the same function. 
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
 
.....to find out what the domain and range are
{  element  :  or  }
range:
{  :  or  }
domain:
{  element  :  }
range:
{  element  :  }
so,  and  are not same because they have different domain and range
 
RELATED QUESTIONS
The functions $f$ and $g$ are defined as follows:
\[f(x) =... (answered by ikleyn)
Consider the functions f and g defined by f(x)=sqrt((x+1)/(x-1)) and... (answered by ikleyn)
Consider the functions
f(x) = sqrt((x+1)/(x-1)) and g(x) = sqrt(x+1)/sqrt(x-1)
Explain... (answered by Theo)
−2x+15y=−24space, minus, 2, x, plus, 15, y, equals, minus, 24
\qquad... (answered by ikleyn,fractalier)
The functions f and g are defined as follows:
f(x) = sqrt(x+1/x-1)    g(x) =... (answered by ikleyn)
Consider two functions, f and g, given by: {{{ f(x)= sqrt ( x-1 ) }}} and {{{ g(x)= sqrt... (answered by jim_thompson5910,CharlesG2)
The functions f and g are defined as follows:
f(x) = sqrt(x+1/x-1) and g(x) =... (answered by ikleyn,greenestamps)
 Consider f(x) = sqrt(4x^2 + 1 ) and g(x) = x + 3 /x^2 . Find the composite functions f... (answered by solver91311)
Find the domain of these functions.
f(x)=7-x^2
g(x)=2x+1/x-1
f(x)=sqrt(x-5)... (answered by solver91311)