SOLUTION: Find the solutions to the equation: x2 + 2x – 8 = 0. a. x = –4, 2 b. x = –3, 5 c. x =

Question 107670: Find the solutions to the equation: x2 + 2x – 8 = 0.
a. x = –4, 2
b. x = –3, 5
c. x = –2, 4
d. x = 4, 4
Found 2 solutions by jim_thompson5910, MathLover1:
Answer by jim_thompson5910(21685) (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Quadratic Formula

Let's use the quadratic formula to solve for x:

Starting with the general quadratic

the general solution using the quadratic equation is:

So lets solve ( notice , , and )

Plug in a=1, b=2, and c=-8

Square 2 to get 4

Multiply to get

Combine like terms in the radicand (everything under the square root)

Simplify the square root (note: If you need help with simplifying the square root, check out this solver)

Multiply 2 and 1 to get 2

So now the expression breaks down into two parts

or

Lets look at the first part:

Add the terms in the numerator

Divide

So one answer is

Now lets look at the second part:

Subtract the terms in the numerator

Divide

So another answer is

So our solutions are:

or

So the answer is A)

Answer by MathLover1(3376) (Show Source):
You can put this solution on YOUR website!
Find the solutions to the equation:

a. = (, )
b. = (, )
c. = (, )
d. = (, )
use quadratic formula:

In the standard form

the roots are:

since you have: , , and
then:

answer is

SOLUTION: Find the solutions to the equation: x2 + 2x – 8 = 0. a. x = –4, 2 b. x = –3, 5 c. x = –2, 4 d. x = 4, 4