SOLUTION: Please solve and state restrictions
{{{(n^2+3n+2)/(n^2+5n+6)}}} minus {{{(2n)/(n+3)}}}
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Question 1075326: Please solve and state restrictions
minus
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
common denominator is (n+3)(n+2)
The numerator will be n^2+3n+2-2n(n+2)= -n^2-n+2=-(n^2+n-2)=-(n+2)(n-1)
The (n+2) will cancel numerator and denominator,
so the answer is
-(n-1)/(n+3)
Check with n=4
30/42-8/7=-18/42 or -3/7
-(3)/7
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