We factor the denominator on the first fraction:



None of the denominators can be 0, so

we must restrict the denominators

n+8≠0,   n+3≠0
  n≠-8,    n≠-3

However we must not divide by 0, so the numerator
of what we are dividing by must not equal 0 either

So the numerator of the second fraction also cannot
be 0, for then the fraction that we are dividing by
would be 0, and we cannot divide by zero.

n+1≠0
  n≠-1

So the restrictions are n≠-8, n≠-3, and n≠-1

To finish the problem, we invert the second fraction
and multiply:



and cancel:






, n≠-8, n≠-3, n≠-1

Edwin