SOLUTION: Simplify and state restrictions
{{{ (n^2+3n+2)/(n^2+5n+6)-(2n)/(n+3) }}}
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Question 1075221: Simplify and state restrictions
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Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
n^2+3n+2/(n+3)(n+2)-2n/(n+3)
=n^2+3n+2-2n(n+2) is numerator
=n^2+3n+2-2n^2-4n=-n^2-n+2=-(n^2+n-2)=-(n+2)(n-1)
That is over (n+3)(n+2)
the (n+2) cancel
it is -(n-1)/(n+3)
n cannot equal -2 or -3
Check
Let n=3
20/30-1=-1/3
-(2/6)=-1/3
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