SOLUTION: 2\sqrt(3x+3)=12

Algebra.Com
Question 1075000: 2\sqrt(3x+3)=12
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
2/sqrt(3x+3)=12; NOTE: I am assuming the radical is a denominator.
1/sqrt(3x+3)=6
sqrt(3x+3)=(1/6) by cross multiplying
3x+3=1/36 by squaring
108x+108=1, by multiplying by 36
108x=-107
x=-0.991
2/sqrt(0.027778)=12
If this is a product, then one would divide both sides by 2, square both sides, and solve for x.

RELATED QUESTIONS

Simplify: 2 sqrt 12 + sqrt... (answered by Earlsdon)
sqrt of 3(2+sqrt of... (answered by jim_thompson5910)
2(sqrt of 3 + sqrt of... (answered by jim_thompson5910)
3 + sqrt 3x - 2 =... (answered by jerrybassmasta)
Simplify sqrt(-12) A. -[sqrt(12)]i B. -2[sqrt(3)] C. [sqrt(12)]i D.... (answered by MathLover1)
sqrt{{{3x/2}}}=sqrt{{{3x}}}/sqrt{{{2}}} (answered by rapaljer)
I'm trying to prove that {{{sqrt(4 - 2 * sqrt(3)) + sqrt(12 - 6 * sqrt(3)) =... (answered by Alan3354)
3x^2 + 2 1/2 x = -2 A x = {-5 +- i[SQRT(71)}/12 Bx = {5 +- i[SQRT(71)]}/12 Cx =... (answered by ewatrrr)
sqrt of 3x + sqrt of 12 = x+5 over sqrt of 3, please... (answered by drk)