SOLUTION: The figure shows the graphs of f(x) = x3 and g(x) = ax3. What can you conclude about the value of a? a. a < –1 b. –1 < a < 0 c. 0 < a < 1 d. 1 < a

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are you sure this is what you need or you need
I guess that cubic function is what you need:

and to see what changes we get if we chaging
here is the graph of :

Solved by pluggable solver: Graph of a cubic equation

now, watch the graph if

a.
we can take and see what is different if we compare it to previous

Solved by pluggable solver: Graph of a cubic equation

now, watch the graph if
b. –1 < a < 0......let , do you see any difference?

Solved by pluggable solver: Graph of a cubic equation

now, watch the graph if
c. < < ......let , do you see any difference?

Solved by pluggable solver: Graph of a cubic equation

now, watch the graph if
d. < .......let

Solved by pluggable solver: Graph of a cubic equation

If a getting smaller and smaller then, graph is getting closer and closer to from to and lies in II and IV quadrant.
Let see the graph for which is very close to …….it is almost straight line which tend to lie on but still goes through II and IV quadrant.

Solved by pluggable solver: Graph of a cubic equation

Let see the graph for which is very distant from …….it is almost straight line which tend to lie on y-axis

Solved by pluggable solver: Graph of a cubic equation

If a getting greater and greater then , graph is getting closer and closer to from to and lies in II and IV quadrant.
Let see the graph for which is very close to …….it is almost straight line which tend to lie on but still goes through I and III quadrant.

Solved by pluggable solver: Graph of a cubic equation

Let see the graph for which is very distant from …….it is almost straight line which tend to lie on but still goes through I and III quadrant.

Solved by pluggable solver: Graph of a cubic equation