SOLUTION: A ball is thrown upward with an initial velocity of 40 feet per second
from ground level. The height of the ball, in feet, after t seconds is
given by h  16t
2
Algebra.Com
Question 1074428: A ball is thrown upward with an initial velocity of 40 feet per second
from ground level. The height of the ball, in feet, after t seconds is
given by h 16t
2 40t. At the same time, a balloon is rising at a
constant rate of 10 feet per second. Its height, in feet, after t seconds
is given by h 10t. Find the time it takes for the ball and the balloon
to reach the same height.
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
Solve the equation
=
to get the answer.
Plot y = (red) and y = (green)
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