SOLUTION: Solve for a: 2log5(3a+1)=log5(4)+2log5(2a-1)
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Question 1072583: Solve for a: 2log5(3a+1)=log5(4)+2log5(2a-1)
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve for a: 2log5(3a+1)=log5(4)+2log5(2a-1)
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log5(3a+1)^2 - log5(2a-1)^2 = log(4)/log(5)
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log5[(3a+1)^2/(2a-1)^2] = 0.8614
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2log5[(3a+1)/(2a-1)] = 0.8614
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log5[(3a+1)/(2a-1)] = 0.4307
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3a+1 = 5^0.4307*(2a-1)
3a+1 = 2(2a-1)
3a+1 = 4a-2
a = 3
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Cheers,
Stan H.
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Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Solve for a: 2log5(3a+1)=log5(4)+2log5(2a-1)
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