SOLUTION: x2 - 10x + y2 + 4y + 13 = 0 a. Find the corresponding standard form b. Identify the center and radius of the circle c. Find the x- and y-intercepts d. Graph the circle

Question 1062324: x2 - 10x + y2 + 4y + 13 = 0
a. Find the corresponding standard form
b. Identify the center and radius of the circle
c. Find the x- and y-intercepts
d. Graph the circle
Found 2 solutions by Alan3354, KMST:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
x2 - 10x + y2 + 4y + 13 = 0
Use ^ (Shift 6) for exponents.
x^2 - 10x + y^2 + 4y = -13
a. Find the corresponding standard form
complete the square for x, and for y.
--------
b. Identify the center and radius of the circle
(x-h)^2 + (j-k)^2 = r^2
Center at (h,k), radius = r
--------------
c. Find the x- and y-intercepts
x-ints at y = 0, y-ints @ x = 0 (if any)
-------------
d. Graph the circle
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
a.

Completing squares:

or

b. The radius is ,
the number squared on the right side of the equation above.
The coordinates of the center are the solution for the shrunken circle with ,
--> -->

c. The x-intercepts:
The x-intercepts are the points (if any) where ,
where the graph of the equation crosses the x-axis.
To find them, we solve
-->-->--> ,
or we solve
-->-->-->-->-->--> .
Theapprocimate values for the y=coordinates of those points are
and .

The y-intercepts:
The y-intercepts are the points (if any) where ,
where the graph of the equation crosses the x-axis.
To find them, we solve
-->-->--> ,
or we solve
-->-->-->--> >
The graph does not cross the y-axis.
In fact, it looks like this:

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