SOLUTION: One-to-one function is h(x)=8x-3/3x+5. Find h^-1(x), where h^-1 is the inverse of h. Also state domain and range of h^-1 in interval notation.
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Question 1061291: One-to-one function is h(x)=8x-3/3x+5. Find h^-1(x), where h^-1 is the inverse of h. Also state domain and range of h^-1 in interval notation.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Use x,y nomenclature.
Interchange x and y,
Domain is all x except,
Determine the range from the domain of the original function,
Since is excluded from h domain, it is also excluded from the inverse's range.
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