SOLUTION: If f(x)=5/x and g(x)=2/2x+1 , find the functions (a,b) and their domains.
a.) (f o g)(x) I did 5/1/2/2x+1 and I multiplied 2 and 1 and multiplied 5 and 2x+1 to get 10x+5/2 . I t
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Question 1052272: If f(x)=5/x and g(x)=2/2x+1 , find the functions (a,b) and their domains.
a.) (f o g)(x) I did 5/1/2/2x+1 and I multiplied 2 and 1 and multiplied 5 and 2x+1 to get 10x+5/2 . I then factored out the 5 in the numerator to get 5(2x+1) (Not positive if I need to factor the numerator or not) and then the denominator stayed at 2. I think the correct answer to this is 5(2x+1)/2 . And the Domain= (-infinity, 1/2)u(1/2, +infinity). (Not sure if this Domain is correct, nor am I sure how I got it).
b.) (g o f)(x) I am not sure how to solve this one. I am stuck at 2/2(5/x)+1. I am not sure how to get the fraction out of the denominator.
Anything helps, thank you.
-Garrett
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Part A
Replace EVERY copy of x with g(x)
Focus only on the right side. Replace g(x) with it's equivalent expression. Now simplify
Since (f o g)(x) is the same as f(g(x)), this means that (f o g)(x) is equal to
The simplified form of the equation above leads to no domain issues. However, if you consider the original function before you simplify, then leads to a division by zero error.
So we must kick that out of the domain.
So the domain of (f o g)(x) is (-infinity, -1/2) U (-1/2, infinity). Any other number works in the domain.
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Part B
Replace EVERY copy of x with f(x)
Plug in f(x) = 5/x. Simplify.
So (g o f)(x) is equivalent to
Here we can't have x equal 0 or -10. Those values make the denominator zero. Any other value will work.
So the domain of (g o f)(x) is (-infinity, -10) U (-10, 0) U (0, infinity)
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