SOLUTION: A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function. What is the maximum height that the ball will reach? h(t)=76t-16t^2 Do not

Question 1041381: A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function. What is the maximum height that the ball will reach?
h(t)=76t-16t^2
Do not round your answer
Answer by ikleyn(52754) (Show Source): You can put this solution on YOUR website!
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A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function.
What is the maximum height that the ball will reach?
h(t)=76t-16t^2
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

They ask you: what is the maximum of this quadratic function: 

h(t) = .     (1)

Do you remember how to find the vertex of the parabola y =  ?

The maximum is reached at x = . 

In your case the maximum height is reached at the time moment t =  =  =  seconds =  seconds. 

Next, to calculate the maximal height, you need to substitute this value of the time t into the formula for the height (1).

Then you get h(t) = h(19/8) =  ft.

You can complete calculations on your own.

For many other similar problems see the lessons
    - Problem on a projectile moving vertically up and down
    - Problem on an arrow shot vertically upward
    - Problem on a ball thrown vertically up from the top of a tower
    - Problem on a toy rocket launched vertically up from a tall platform
in this site.

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