SOLUTION: When an object moves in a circular path, the centripetal force F varies directly as the square of the velocity v and inversely as the radius r of the circle. If F=200 when v=6 and

Question 1034274: When an object moves in a circular path, the centripetal force F varies directly as the square of the velocity v and inversely as the radius r of the circle. If F=200 when v=6 and r=5, find F when v=4 and r=8.
Help would be so appreciated. Thank you
Answer by ikleyn(52786) (Show Source): You can put this solution on YOUR website!
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When an object moves in a circular path, the centripetal force F varies directly as the square of the velocity v and
inversely as the radius r of the circle.
If F=200 when v=6 and r=5, find F when v=4 and r=8.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

 
First statement is translated as 

F =          (1)

with the constant k.


Next statement ". . . F=200 when v=6 and r=5" is translated as 

200 = .      (2)  

(simply plug in your  data into the formula (1)). Simplify (2) to get

200 =   and then obtain  k =  = .

Now "find F when v=4 and r=8."
Use the formula (1) and the value k = :

F =  =  = 34.72.

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