SOLUTION: solve for x x^4+2x/x^2-1=0 in a solution they got =>(x^4+2x)(x^2-1)/(x^2-1)^2 =0 and then =>x=-2^(1/3),-1,0,1 how did they get this? Thanks in advance!

Question 1025161: solve for x
x^4+2x/x^2-1=0 in a solution they got
=>(x^4+2x)(x^2-1)/(x^2-1)^2 =0
and then =>x=-2^(1/3),-1,0,1
how did they get this? Thanks in advance!
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
I think this is your equation although you didn't use any parentheses.

So you need to solve when the numerator is equal to zero,

Two solutions:

and

Not sure about the other two solutions.
I also looked at

But that didn't yield your solutions either.
If you need repost and add parentheses to your equation.
RELATED QUESTIONS
Solve for x:... (answered by richwmiller)

x-3/4-2x - 1/x-2 + 1 =... (answered by jim_thompson5910)

Solve... (answered by RAY100)

Please help with this equation: 2x+z+3w=0 -x+2y-z-2w=2 x-y+w=2 I did this: 2 0 1 (answered by Alan3354)

(x-4)�+8=0 (x+2)�=3(x+2) (2x-1)�=(x+1)� 2x(x+4)=(x-3)(x-3) (answered by josgarithmetic)

2x^2+x-1=0 (answered by checkley77)

x^2+2x+1=0 (answered by uday1435)

X^2-2x+1 =... (answered by MathLover1)

Please help me solve this problem: y^4/3 = -3y This is what I have done: y^4/3 +... (answered by stanbon,ankor@dixie-net.com)