SOLUTION: A rocket is launched from the top of a cliff that is 80 feet high with an initial velocity of 80 feet per second. The height, h(t), of the rocket after t seconds is given by the eq

Question 1002781: A rocket is launched from the top of a cliff that is 80 feet high with an initial velocity of 80 feet per second. The height, h(t), of the rocket after t seconds is given by the equation....
h(t)=-16t^2 + 80t + 80
How long after the rocket is launched will it strike the ground? Round to the nearest tenth of a second, if necessary.
Answer by fcabanski(1391) (Show Source): You can put this solution on YOUR website!

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