Questions on Algebra: Rational Functions, analyzing and graphing answered by real tutors!

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Tutors Answer Your Questions about Rational-functions (FREE)


Question 571790: find a third-degree polynomial equation with rational coefficients that has 1 and 3i as roots.
Answer by KMST(592) About Me  (Show Source):
You can put this solution on YOUR website!
If the coefficients are rational numbers, irrational roots have to appear in conjugate pairs, so -3i must also be a root.
A polynomial of degree 3, with 1, 3i, and -3i as roots has to be equal to
K%28x-1%29%28x-3i%29%28x%2B3i%29 with some rational non-zero number K, and all polynomials of such form are of degree 3, and have 1, 3i, and -3i as roots.
So there are infinite such polynomials for the answer, but the simplest, with K=1 is
%28x-1%29%28x-3i%29%28x%2B3i%29=%28x-1%29%28x%5E2%2B9%29=x%5E3-x%5E2%2B9x-9


Question 571614: How would you perform the indicated operation and simplify 6x over x+1plus 7 over x-1 minus 12 over x²-1?
6x/x+1+7/x–1– 12/x² –1
margarida183@hotmail.com





Answer by KMST(592) About Me  (Show Source):
You can put this solution on YOUR website!
The problem is
6x/(x+1)+7/(x–1)–12/(x²–1) = 6x/(x+1)+7/(x-1)-12/(x^2-1) = 6x%2F%28x%2B1%29+7%2F%28x-1%29-12%2F%28x%5E2-1%29
You need a common denominator
%28x%2B1%29%28x-1%29=x%5E2-1 would work, so
6x%2F%28x%2B1%29+7%2F%28x-1%29-12%2F%28x%5E2-1%29=6x%28x-1%29%2F%28%28x%2B1%29%28x-1%29%29%2B7%28x%2B1%29%2F%28%28x-1%29%28x%2B1%29%29-12%2F%28%28x%2B1%29%28x-1%29%29=%286x%5E2-6x%29%2F%28%28x%2B1%29%28x-1%29%29+%287x%2B7%29%2F%28%28x-1%29%28x%2B1%29%29-12%2F%28%28x%2B1%29%28x-1%29%29=%286x%5E2-6x%2B7x%2B7-12%29%2F%28%28x%2B1%29%28x-1%29%29=%286x%5E2%2Bx-5%29%2F%28%28x%2B1%29%28x-1%29%29


Question 571552: a plus 1 over 4 minus a over 6
Answer by Edwin McCravy(6933) About Me  (Show Source):
You can put this solution on YOUR website!
a + 1%2F4 - a%2F6

Write a as a%2F1

a%2F1 + 1%2F4 - a%2F6

The LCD is 12.

The denominator of a%2F1 needs to be multiplied by 12 to become
the LCD of 12, so multiply the first fraction by red%28%2812%29%2F%2812%29%29

a%2F1red%28%2812%29%2F%2812%29%29 + 1%2F4 - a%2F6

The denominator of 1%2F4 needs to be multiplied by 3 to become
the LCD of 12, so multiply the second fraction by red%28%283%29%2F%283%29%29

a%2F1red%2812%2F12%29 + 1%2F4red%28%283%29%2F%283%29%29 - a%2F6

The denominator of a%2F6 needs to be multiplied by 2 to become
the LCD of 12, so multiply the third fraction by red%28%282%29%2F%282%29%29

a%2F1red%28%2812%29%2F%2812%29%29 + 1%2F4red%28%283%29%2F%283%29%29 - a%2F6red%28%282%29%2F%282%29%29

Multiply the numerators and the denominators in each of the the three
terms:

%2812a%29%2F12 + 3%2F12 - 2a%2F12

Now that all three fractions have the same denominator, we combine
the three numerators and write that over the LCD of 12:

%2812a%2B3-2a%29%2F12


Combine the like terms 12a and -2a and get 10a.

So the final simplification is

%2810a%2B3%29%2F12

Edwin



Question 571548: 3 over x plus 1 minus 4 over x
Answer by stanbon(48535) About Me  (Show Source):
You can put this solution on YOUR website!
3 over x plus 1 minus 4 over x
---
3/(x+1) - (4/x)
---
lcd: x(x+1)
----
Rewrite each fraction with the lcd as its denominator:
[3x/lcd] - 4(x+1)/lcd
----
Combine the numerators over the lcd:
= [3x-4x-4]/lcd
---
= -[x+4]/[x(x+1)]
=========================
Cheers,
Stan H.
=============


Question 571531: I am having a hard time coming up with the answer for this problem
-8/1/2^2 - 4
-8/(1/2)(1/2) -4
-8/.25-4
From here I don't know how do finish the problem However the answer is 32/15
I need to know the rest of the way on how to get there.

Answer by stanbon(48535) About Me  (Show Source):
You can put this solution on YOUR website!
-8/1/2^2 - 4
-8/[(1/2)(1/2)] -4
[-8/.25]-4
Invert that denominator and multiply to get:
= -32-4
= -36
===============
Cheers,
Stan H.


Question 571401: i still have problems with this...
6b-3/b+4

Answer by stanbon(48535) About Me  (Show Source):
You can put this solution on YOUR website!
i still have problems with this...
6b-3/b+4
---
Assuming there are no parentheses you get:
6b - (3/b) +4
----
lcd = b
----
Rewrite each term with the lcd as its denominator:
(6b^2)/lcd - (3/lcd) + (4b/lcd)
-----
Combine the numerators over the lcd:
-----
(6b^2-3+4b)/b
======================
Note: If there are parentheses you should post them.
======================
Cheers,
Stan H.


Question 570933: how do i answer the question: list all possible rational zeros of each equation, with equations like x^3-7x+6=0? i have worked out the equation using synthetic division, but that takes too long, is there a faster way?
Answer by Edwin McCravy(6933) About Me  (Show Source):
You can put this solution on YOUR website!
If you're only asked to list all POSSIBLE rational zeros,
then they are NOT asking you to find the zeros. 

They are merely asking you to list all the CANDIDATES for 
rational zeros.

It is unfortunate that all the algebra books use the word
"POSSIBLE" and ask for all "possible rational zeros".  But 
they do!  They should say "candidates for rational zeros", 
because many times the candidates are not really "possible".

If a polynomial has rational zeros, then those rational zeros 
will be fractions of this form: 

                %27%27+%2B-+%28factor_of_the_constant_term%29%2F%28factor_of_the_leading_coefficient%29 

However, not all fractions of this form are necessarily zeros of the
polynomial. Indeed it may happen that none of the fractions so formed
are actually zeros of the polynomial.

Since the leading coefficient is 1, you need not worry about denominators
in this polynomial.  All they want you to do is list all the positive and
negative factors of the last term, 6, which are 

                ±1, ±2, ±3, ±6

The only thing they are asking you to do is to list those!   

Since you have already found all the zeros, you know that they are
-3, 1 and 2.  So you see that +3,-1,-2,+6, and -6 are not zeros at all.
However they were CANDIDATES for aeros and so you should list all
the candidates for solutions.  

I think you were misled, and understandably so, by the word "POSSIBLE".
I wish they would use another word.

Edwin


Question 570598: I do not really understand how to do this...
sqrt(3x+17) - 5 = x

Answer by mananth(10546) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%283x%2B17%29+-+5+=+x
sqrt%283x%2B17%29+=+x%2B5
square both side of the equation
3x%2B17+=+%28x%2B5%29%5E2

3x%2B17+=+x%5E2%2B10x%2B25

x^2+7x+8=0
Find the roots of the equation by quadratic formula

a= 1 b= 7 c= 8

b^2-4ac= 49 - -32
b^2-4ac= 17
sqrt%28%0917%09%29= 4.12
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=( -7 + 4.12 )/ 2
x1= -1.44

x2=( -7 -4.12 ) / 2
x2= -5.56



Question 570575: Solve the following equations.
Square root 2x+3-7=0

Answer by Alan3354(21583) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the following equations.
Square root 2x+3-7=0
------------
I see only one.
Square root 2x+3-7=0
sqrt%282%29x+%2B+3+-+7+=+0
sqrt%282%29x+-+4+=+0
sqrt%282%29x+=+4
Square both sides
2x%5E2+=+16
x+=+sqrt%288%29
or x+=+2sqrt%283%29


Question 570425: It takes 16 minutes to fill a tub with a stopper. It takes 20 minutes to empty a tub without a stopper. How long does it take to fill a tub without a stopper?
Answer by scott8148(5880) About Me  (Show Source):
You can put this solution on YOUR website!
in the 16 min that it normally takes to fill, 4/5 (16/20) of the tub has drained

so it takes 16 min to fill 1/5 of the tub


Question 569433: i need help evaluating this expression. 1/81 to the -3/4
Answer by josmiceli(6783) About Me  (Show Source):
You can put this solution on YOUR website!
+%281%2F81%29%5E%28%28-3%2F4%29%29+
--------
+81%5E%28%28+3%2F4+%29%29+
--------
+%28+3%5E4+%29%5E%28%28+3%2F4+%29%29+
--------
++3%5E%2812%2F4%29++
--------
+3%5E3+=+27+ answer


Question 569246: when you have a number in front of x and y... how do you find the slope?? how do you find the x and y intercept in an easy way?? how do you graph an equation that is in standard form?? EXAMPLE: 3x+2y=6 how do you graph it??
Answer by scott8148(5880) About Me  (Show Source):
You can put this solution on YOUR website!
easy way for intercepts

x equals zero at the y-intercept and y equals zero at the x-intercept

take the standard form equation and ignore the term that your not finding the intercept of (because the term equals zero)

3x + 2y = 6 ___

ignoring the y-term ___ 3x = 6 ___ x = 2 ___ the x-intercept is (0,2)

ignoring the x-term ___ 2y = 6 ___ y = 3 ___ the y-intercept is (3,0)

graph the equation by locating the two intercepts and drawing the line through the two points

the slope is also easy ___ -(y-intercept) / (x-intercept) ___ -3 / 2


Question 568941: (-2-x)^ 0.5 -x= 2
Answer by lwsshak3(2915) About Me  (Show Source):
You can put this solution on YOUR website!
(-2-x)^ 0.5 -x= 2
(-2-x)^ 0.5 = 2+x
square both sides
-2-x=4+4x+x^2
x^2+5x+6=0
(x+3)(x+2)=0
x=-3
or
x=-2


Question 568687: Please Help. I'm horrible with radicals!
Simplify each radical expression. Use absolute value symbols when needed.
1.) ∛-27x^6
2.) √a^4b^2
3.) 5th root√-32s^15t^10
4.) ∜256y^8
5.) (2-√5)(2+√5)
6.) √48a^5b / √12ab
7.) √5(2√45-√5)
8.) 7/1-√3
9.) 5√32-7√8
10.) 2√15xy^3 x 3√30x^3y^2

Found 2 solutions by KMST, mananth:
Answer by KMST(592) About Me  (Show Source):
You can put this solution on YOUR website!
Hopefully, what I could interpret from your posting is what you meant
1) root%283%2C-27x%5E6%29
Since %28-3%29%5E3=-27 and %28x%5E2%29%5E3=x%5E%282%2A3%29=x%5E6,
root%283%2C-27x%5E6%29=root%283%2C%28-3%29%5E3%28x%5E2%29%5E3%29=root%283%2C%28-3x%5E2%29%5E3%29=-3x%5E2
2) sqrt%28a%5E4b%5E2%29=sqrt%28%28a%5E2%29%5E2%2Ab%5E2%29=sqrt%28%28a%5E2%29%5E2%29%2Asqrt%28b%5E2%29=a%5E2abs%28b%29 because sqrt%28b%5E2%29=abs%28b%29
Example:
If b=5, sqrt%285%5E2%29=sqrt%2825%29=5=b, but
if b=-5, sqrt%28%28-5%29%5E2%29=sqrt%2825%29=5=abs%28-5%29=abs%28b%29
3) root%285%2C-32s%5E15t%5E10%29
Since %28-2%29%5E5=-32, %28s%5E3%29%5E5=s%5E%283%2A5%29=s%5E15, and %28t%5E2%29%5E5=t%5E%282%2A5%29=t%5E10,
root%285%2C-32s%5E15t%5E10%29=root%285%2C%28-2%5E5%29%28s%5E3%29%5E5%28t%5E2%29%5E5%29=root%285%2C%28-2s%5E3t%5E2%29%5E5%29=-2s%5E3t%5E2
4) root%284%2C256y%5E8%29=root%284%2C2%5E8y%5E8%29=root%284%2C2%5E8%29%2Aroot%284%2Cy%5E8%29=root%284%2C%282%5E2%29%5E4%29%2Aroot%284%2C%28y%5E2%29%5E4%29=2%5E2y%5E2=4y%5E2
5) %282-sqrt%285%29%29%282%2Bsqrt%285%29%29=2%5E2-%28sqrt%285%29%29%5E2%29=4-5=-1
6) sqrt%2848a%5E5b%29%2Fsqrt%2812ab%29=sqrt%2848a%5E5b%2F%2812ab%29%29=sqrt%28%2848%2F12%29%28a%5E5%2Fa%29%28b%2Fb%29%29+=sqrt%284a%5E4%29=sqrt%284%29%2Asqrt%28a%5E4%29=2a%5E2
7) sqrt%285%29%282sqrt%2845%29-sqrt%285%29%29=2%2Asqrt%285%29%2Asqrt%2845%29-sqrt%285%29%2Asqrt%285%29=2%2Asqrt%285%2A45%29-5=2sqrt%28225%29-5=2%2A15-5=30-5=25
8) 7/%281-sqrt%283%29%29=7%2F%281-sqrt%283%29%29=%0D%0A%287%2F%281-sqrt%283%29%29%29%28%281%2Bsqrt%283%29%29%2F%281%2Bsqrt%283%29%29%29=+7%281%2Bsqrt%283%29%29%2F%28%281-sqrt%283%29%29%281%2Bsqrt%283%29%29%29=%287%2B7sqrt%283%29%29%2F%281%5E2-%28sqrt%283%29%29%5E2%29=%287%2B7sqrt%283%29%29%2F%281-3%29=%287%2B7sqrt%283%29%29%2F%28-2%29=-7%2F2-7sqrt%283%29%2F2
9) 5sqrt%2832%29-7sqrt%288%29=5sqrt%284%2A8%29-7sqrt%288%29=5%2Asqrt%284%29%2Asqrt%288%29-7%2Asqrt%288%29=+5%2A2%2Asqrt%288%29-7%2Asqrt%288%29=10sqrt%288%29-7sqrt%288%29=3sqrt%288%29
You can simplify it further:
3sqrt%288%29=3sqrt%284%2A2%29=3%2Asqrt%284%29%2Asqrt%282%29=6%2A2sqrt%282%29=6sqrt%282%29
10) 2sqrt%2815xy%5E3%29%2A3sqrt%2830x%5E3y%5E2%29=2%2A3%2Asqrt%2815xy%5E3%29%2Asqrt%2830x%5E3y%5E2%29=6sqrt%28%2815xy%5E3%29%2A%2830x%5E3y%5E2%29%29=6sqrt%28450x%5E4y%5E5%29=6%2Asqrt%28450%29%2Asqrt%28x%5E4%29%2Asqrt%28y%5E5%29=6%2Asqrt%28225%2A2%29%2Ax%5E2%2Asqrt%28y%5E4y%29=6sqrt%28225%29sqrt%282%29x%5E2sqrt%28y%5E4%29sqrt%28y%29=6%2A15%2Asqrt%282%29x%5E2y%5E2sqrt%28y%29=90x%5E2y%5E2sqrt%282%29sqrt%28x%29sqrt%28y%29=90x%5E2y%5E2sqrt%282xy%29

Answer by mananth(10546) About Me  (Show Source):
You can put this solution on YOUR website!
1.) ∛-27x^6 =+-3x%5E2
2.) √a^4b^2 = a%5E2b
3.) 5th root√-32s^15t^10 = +-2s%5E3t%5E2
4.) ∜256y^8= 4y%5E2
5.) (2-√5)(2+√5)= -1
6.) √48a^5b / √12ab = 4a%5E4
7.) √5(2√45-√5)=25
8.) 7/1-√3 = %28-7%2F2%29+%2B7sqrt%283%29%2F2
9.) 5√32-7√8 = 6sqrt%282%29
10.) 2√15xy^3 x 3√30x^3y^2 = 90sqrt%282%2Ax%5E4%2Ay%5E5%29
You can find out the absolute values on a calculator


Question 568455: 2. Biologists want to set up a station to test alligators in the lake for West Nile Virus. Suppose that the costs for such a station are $2,750 for setup costs and $4.50 to administer each test.
a. Write an expression that gives the total cost to test x animals.
So far I have C(x)/x = 2750(4.5)/x...but I am not confident that is the right expression.
b. You can find the average cost per animal by dividing total costs by number of animals. Write the expression that gives the average cost per animal. x should be the only variable.
Wouldn't that be the answer I just stated above??
c. Find the average cost per animal for 10 animals, 100 animals, and 1,000 animals.
d. As the number of animals tested increases, what happens to the average cost to test the animals? Would the average cost ever fall below $4.50? If so, identify a value that supports your answer. If not, explain how you know.
e. How many animals should be tested for the average cost to be $9.50 per animal?
If I could understand the concept behind this rational expression exercise I can probably answer the last two (d and e) by myself. Am I right with my initial attempt at the expression? If not, can you please show me where I am wrong and explain it? Thanks in advance!

Answer by KMST(592) About Me  (Show Source):
You can put this solution on YOUR website!
Before testing any animals, you spend $2,750. You need to spend that much to buy equipment before you start. You can use that equipment over and over, once you catch your first alligator, but you cannot start without that initial expense.
So for x=0 you already spent C%280%29=2750.
Testing each animal costs and additional $4.50. So for one animal you spend $4.50, after the initial $2750 you had to spend just to start. If you tested 10 animals, it would cost the initial $2,750, plus $45 ($4.50 times 10).
So, if you test x aminals you will spend $4.50%2Ax in addition to the $2,750 you had spend for set up before you started testing animals.
The total cost for testing those x animals is
C%28x%29=2750%2B4.5x
The answer to part a. is highlight%28C%28x%29=2750%2B4.5x%29
b. The average cost per animal is
A%28x%29=C%28x%29%2Fx=%282750%2B4.5x%29%2Fx=2750%2Fx%2B4.5x%2Fx=2750%2Fx%2B4.5
highlight%28A%28x%29=2750%2Fx%2B4.5%29


Question 568293: 4/x^2+3x-10 how do you find the holes and graph this equation? What is the method to solving this step by step?
Answer by lwsshak3(2915) About Me  (Show Source):
You can put this solution on YOUR website!
4/x^2+3x-10 how do you find the holes and graph this equation? What is the method to solving this step by step?
**
The first step is to write the equation in factored form:
y=4/(x^2+3x-10)=4/(x+5)(x-2)
y-intercept: none (because numerator is a constant)
..
x-intercept: set x=0, then solve for y
y=4/-10=-2/5=-.4
..
Horizontal asymptote: lf the degree of the numerator is less than the degree of the denominator, horizontal asymptote is the x-axis or y=0.
..
Vertical asymptotes: Set denominator=0, then solve for x:
(x+5)(x-2)=0
x=-5
and
x=2
so you have vertical asymptotes at x=-5 and x=2
..
and lastly, draw a number line with the zeros on it:
<...+.....-5.....-.......2.....+......>
This shows from (-∞,-5) the function is>0
Between (-5,2) the function<0
From(2,∞) the function is again>0
..
You now have all the information you need to graph the function.


Question 568277: Find the variation constant and an equations and variables where y varies inversely as x and y=9 when x=13
Answer by stanbon(48535) About Me  (Show Source):
You can put this solution on YOUR website!
Find the variation constant and an equations and variables where
y varies inversely as x
---
y = k/x
Solve for "k" using "y=9 when x=13".
-----
9 = k/13
k = 13*9
k = 117
===============
Cheers,
Stan H.
==============


Question 568222: Please help! Having so much trouble with these last 3 problems!
Divide and simplify.
4.) ∛270x / ∛10xy^2

Rationalize the denominator of each expression.
5.) √7x / √3

6.) ∛x^2 / ∛4''.

Answer by Alan3354(21583) About Me  (Show Source):
You can put this solution on YOUR website!
Divide and simplify.
4.) ∛270x / ∛10xy^2
= root%283%2C%28270x%2F10xy%5E2%29%29
= root%283%2C%2827%2Fy%5E2%29%29
= root%283%2C%2827y%2Fy%5E3%29%29
= 3%2Aroot%283%2C%28y%29%29%2Fy

Rationalize the denominator of each expression.
5.) sqrt%287x%29%2Fsqrt%283%29+=+sqrt%2821x%29%2Fsqrt%289%29
= sqrt%2821x%29%2F3
------------------------------
6.) root%283%2Cx%5E2%29%2Froot%283%2C4%29
= root%283%2C2x%5E2%29%2Froot%283%2C8%29
= root%283%2C2x%5E2%29%2F2


Question 568035: There are 1000 questions. What is the probablity of two people picking three questions and two of the questions being the same.
Answer by stanbon(48535) About Me  (Show Source):
You can put this solution on YOUR website!
There are 1000 questions. What is the probablity of two people picking three questions and two of the questions being the same
-----
# of ways to pick 2 questions the same: 1
# of ways to pick 1 question different: 997
----
# of ways to pick 3 questions randomly: 1000C3
----
P(pick 2 the same and 1 different) = 997/166167000
=====================
Cheers,
Stan H.


Question 567927: x-1 over x squired +7x+6 + 4 over x squire-3x-4 + 14 over x squire+ 2x-24
Answer by mananth(10546) About Me  (Show Source):
You can put this solution on YOUR website!
x-1 over x squired +7x+6 + 4 over x squire-3x-4 + 14 over x squire+ 2x-24
%28%28x-1%29%2F%28x%5E2%2B7x%2B6%29%29%2B+%28%284%29%2F%28x%5E2-3x-4%29%29%2B%28%2814%29%2F%28x%5E2%2B2x-24%29%29

%28%28x-1%29%2F%28x%2B6%29%28x%2B1%29%29%2B+%28%284%29%2F%28x-4%29%28x%2B1%29%29%2B%28%2814%29%2F%28x%2B6%29%28x-4%29%29%29

LCD = (x+6)(x+1)(x-4)

%28%28x-1%29%28x-4%29%2B4%28x%2B6%29%2B14%28x%2B1%29%29%2F%28%28x%2B6%29%28x%2B1%29%28x-4%29%29

%28x%5E2-5x%2B4%2B4x%2B24%2B14x%2B14%29%2F%28%28x%2B6%29%28x%2B1%29%28x-4%29%29

%28x%5E2%2B13x%2B42%29%2F%28%28x%2B6%29%28x%2B1%29%28x-4%29%29

%28%28x%2B6%29%28x%2B7%29%29%2F%28%28x%2B6%29%28x%2B1%29%28x-4%29%29
%28x%2B7%29%2F%28%28x%2B1%29%28x%2B4%29%29

m.ananth@hotmail.ca





Question 567808: factor 3x^3 +33x^2 +90x
Answer by Earlsdon(6099) About Me  (Show Source):
You can put this solution on YOUR website!
Factor:
3x%5E3%2B33x%5E2%2B90x First factor 3x.
3x%28x%5E2%2B11x%2B30%29 Now factor the trinomial.
3x%28x%2B5%29%28x%2B6%29


Question 567728: I have been working on this problem -4(8+5)-10 8/5 for awhile and I can not seem to understand it.
Answer by stanbon(48535) About Me  (Show Source):
You can put this solution on YOUR website!
-4(8+5)-10 8/5
----------------
= -4(13) - (58/5)
---
= -52 - (58/5)
---
= -(260/5)-(58/5)
----
= -318/5
---
= -63 3/5
==============
Cheers,
Stan H.
==============


Question 567287: I need help writing a polynomial function with rational coefficients in standard form with the given zeros 2,3,5.
Answer by htmentor(580) About Me  (Show Source):
You can put this solution on YOUR website!
I need help writing a polynomial function with rational coefficients in standard form with the given zeros 2,3,5.
=====================
Since the zeros are 2,3,5 we can write the factored equation as
(x-2)(x-3)(x-5)
Multiplying the factors and collecting terms gives:
x^3-10x^2+31x-30
As a check, we can see read off the zeros from graph of the function:
graph%28300%2C300%2C-8%2C8%2C-8%2C8%2Cx%5E3-10x%5E2%2B31x-30%29


Question 566830: without a calculator, sketch the following function. Make sure to label both the x and y intercepts. (Hint: find the zeroes and y-intercept in terms of c)
Answer by Alan3354(21583) About Me  (Show Source):
You can put this solution on YOUR website!
without a calculator, sketch the following function. Make sure to label both the x and y intercepts. (Hint: find the zeroes and y-intercept in terms of c)
---------------
Any function in particular?


Question 566829: simplipfy
s-r over 1/r-1/s

Answer by jim_thompson5910(21667) About Me  (Show Source):
You can put this solution on YOUR website!
(s-r)/(1/r - 1/s)


(s*rs-r*rs)/((1/r)*rs - (1/s)*rs)


(rs^2-r^2s)/(s - r)


(rs(s-r))/(s - r)


rs


So (s-r)/(1/r - 1/s) = rs for all values of r and s where r does not equal s, and neither s nor r are zero.


-------------------------------------------------------------------------------------------------
If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim

-------------------------------------------------------------------------------------------------


Question 566741: √a + √b = √(a+b)
is this true or false
i believe i am correct saying false as the radican are different even though the index are alike

Answer by Alan3354(21583) About Me  (Show Source):
You can put this solution on YOUR website!
√a + √b = √(a+b)
is this true or false
i believe i am correct saying false as the radican are different even though the index are alike
------------------
It's false.
sqrt%28144+%2B+25%29+=+13
sqrt%28144%29+%2B+sqrt%2825%29+=+17


Question 565932: x^2/3x+15-25/3x+15
Answer by Maths68(1150) About Me  (Show Source):
You can put this solution on YOUR website!
=x%5E2%2F%283x%2B15%29-25%2F%283x%2B15%29
Take LCD
=%28x%5E2-25%29%2F%283x%2B15%29
=%28x%5E2-%285%29%5E2%29%2F3%28x%2B5%29
=%28x-5%29%28x%2B5%29%2F3%28x%2B5%29
=%28x-5%29cross%28%28x%2B5%29%29%2F3cross%28%28x%2B5%29%29
=%28x-5%29%2F3%29
=x%2F3-5%2F3%29
=x%2F3-1%262%2F3%29


Question 565468: expand (2a-1)^4 by using pascal's triangle
andreajuni@yahoo.com

Answer by scott8148(5880) About Me  (Show Source):
You can put this solution on YOUR website!
______ 1
_____ 1 1
____ 1 2 1
___ 1 3 3 1
__ 1 4 6 4 1


1(2a - 1)^4 + 4(2a - 1)^3 + 6(2a - 1)^2 + 4(2a - 1)^1 + 1(2a - 1)^0


Question 565050: No matter how hard i try to learn this lesson, I'm stumped. Please help.
Multiply.
1.) ∛4 x ∛2000

Simplify.
2.)∛-243x^3y^10

Multiply and simplify.
3.)√18x^3 x √2x^2y^3

Divide and simplify.
4.) ∛270x / ∛10xy^2

Rationalize the denominator of each expression.
5.) √7x / √3

6.) ∛x^2 / ∛4

Answer by josmiceli(6783) About Me  (Show Source):
You can put this solution on YOUR website!
The general rules are :
+root%28+b%2C+a+%29+%2A+root%28+b%2C+c+%29+=+root%28+b%2C+a%2Ac+%29+
+root%28+b%2C+a+%29+%2F+root%28+b%2C+c+%29+=+root%28+b%2C+%28a%2Fc%29%29+
-----------------
+root%283%2C4%29+%2A+root%28+3%2C+2000+%29+=+root%28+3%2C+4%2A2000+%29+
++root%28+3%2C+4%2A2000+%29+=+root%28+3%2C+8000+%29+
++root%28+3%2C+8000+%29+=+root%28+3%2C+20%5E3+%29+
+root%28+3%2C+20%5E3+%29+=+20+
--------------------
+root%28+3%2C+-243%2Ax%5E3%2Ay%5E10+%29+
+root%28+3%2C+-243+%29+%2A+root%28+3%2C+x%5E3+%29+%2A+root%28+3%2C+y%5E9%2Ay+%29+
+root%28+3%2C+%28-27%29%2A9+%29+%2A+x+%2A+root%28+3%2C+y%5E9+%29+%2A+root%28+3%2C+y+%29+
+-3%2A+root%28+3%2C+9+%29+%2A+x+%2A+y%5E3++%2A+root%28+3%2C+y+%29+
+-3x+%2A+y%5E3+%2A+root%28+3%2C+9y+%29+
--------------------
+sqrt%28+18x%5E3+%29+%2A+sqrt%28+2x%5E2%2Ay%5E3+%29+
+sqrt%28+36x%5E5+%2A+y%5E3+%29+
+sqrt%2836%29+%2A+sqrt%28+x%5E5+%29+%2A+sqrt%28+y%5E3+%29+
+6+%2A+sqrt%28+x%5E4+%29+%2A+sqrt%28x%29+%2A+sqrt%28y%5E2%29+%2A+sqrt%28y%29+
+6x%5E2%2Ay%2A+sqrt%28x%29++%2A+sqrt%28y%29+
+6x%5E2+%2A+y+%2A+sqrt%28+x%2Ay+%29+
----------------------
This is all I have time for.
Hope you get the idea



Question 565028: I need help on functions... for example like this homework question. f(x)= 3x+5 and g(x)=x^2 my problem is what is the funtion for f(x)+g(x)
Answer by ad_alta(170) About Me  (Show Source):
You can put this solution on YOUR website!
The answer is simple: just add the functions! f(x)+g(x)=[3x+5]+[x^2]=x^2+3x+5


Question 564851: Let ƒ(x) = 3x2 – 2x and g(x) = x – 6. Find the value of (f/g)(-1)
Answer by ad_alta(170) About Me  (Show Source):
You can put this solution on YOUR website!
(f/g)(x)=(3x^2-2x)/(x-6), so (f/g)(-1)=-5/7.


Question 564628: Find all numbers for which the rational expression is undefined.
(p^3-7p)/(p^2-9)

Answer by ad_alta(170) About Me  (Show Source):
You can put this solution on YOUR website!
We need to make sure the denominator is nonzero. This happens when p=3,-3. These are all the numbers for which the expression is undefined, since the numerator is well defined for all reals.


Question 564236: Let ƒ(x) = 3x2 – 2x and g(x) = x – 6.
(f/g)(-1)=
solve equations:
(4x-3)^3/2=8
(-2-x)^0.5-x=2
I am a mom trying to help my daughter and I just don't get it!

Answer by stanbon(48535) About Me  (Show Source):
You can put this solution on YOUR website!
Let ƒ(x) = 3x^2 – 2x and g(x) = x – 6.
--------------------------
(f/g)(-1)= = f(-1)/g(-1)
= [3(-1)^2-2(-1)]/[-1-6]
= [3*1+2]/[-7]
= -5/7
==============================
solve equations:
(4x-3)^3/2=8
(4x-3) = 8^(2/3)
(4x-3) = 2^2
4x-3 = 4
4x = 7
x = 7/4
==============================
(-2-x)^0.5-x = 2
---
sqrt(-2-x) = x +2
---
Square both sides:
-2-x = x^2+4x+4
x^2+5x+6 = 0
Factor:
(x+3)(x+2) = 0
x = -2 or x = -3
--
Checking those "answers":
(-2-x)^0.5-x = 2
Check x = -2:
(-2+2)^(0.5) +2 = 2
sqrt(0) + 2 = 2
2 = 2
----
Check x = -3
(-2+3)^(0.5) + 3 = 2
sqrt(1)+3 = 2
4 = 2
False
---
Only solution: x = -2
=============================
Cheers,
Stan H.
=============================


Question 561394: how would you do this if the exponent is a negative such as something that looks like this 64^-2/3?
Answer by lwsshak3(2915) About Me  (Show Source):
You can put this solution on YOUR website!
how would you do this if the exponent is a negative such as something that looks like this 64^-2/3?
**
There is a rule in algebra which says if you move a term with an exponent from numerator to denominator or vise-versa, the sign of the exponent reverses.
64^-2/3=1/64^2/3=1/16


Question 561931: Graph the relation y=2x^2-2 and it's inverse.
Answer by lwsshak3(2915) About Me  (Show Source):
You can put this solution on YOUR website!
Graph the relation y=2x^2-2 and it's inverse
Inverse:
x=2y^2-2
y^2=(x+2)/2
y=√[(x+2)/2]
See graph below:
y=±((x+2)/2)^.5
+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C%28%28x%2B2%29%2F2%29%5E.5%2C-%28%28x%2B2%29%2F2%29%5E.5%2C2x%5E2-2%29+


Question 562701: when I have the equation square root of(x+5)=2*square root of (x-3) + 1 how do I start that?
Answer by lwsshak3(2915) About Me  (Show Source):
You can put this solution on YOUR website!
when I have the equation square root of(x+5)=2*square root of (x-3) + 1 how do I start that?
**
√(x+5)=2√(x-3)+1
square both sides
x+5=4(x-3)+4√(x-3)+1
distribute, combine like terms and isolate radical
x+5=4x-12+4√(x-3)+1
-3x+16=4√(x-3)
square both sides again
9x^2-96x+256=16(x-3)=16x-48
9x^2-112x+304=0
(x-4)(9x-76)=0
x=4
or
x=76 (reject, does not check-extraneous root)


Question 562041: Rational Zero Theorem
How do you factor
f(x)= 4x^3-8x^2-29x-12

Answer by lwsshak3(2915) About Me  (Show Source):
You can put this solution on YOUR website!
How do you factor
f(x)= 4x^3-8x^2-29x-12
**
Use Rational Roots Theorem to Solve:
....0...|.....4........-8.......-29..........-12.........
....1...|.....4........-4.......-33..........-45........
....2...|.... 4........ 0........-29..........-70.........
....3...|.....4.........4........-17..........-63.....
....4...|.....4.........8...........3..............0 (4 is a root)
f(x)=(x-4)(4x^2+8x+3
f(x)=(x-4)(2x+1)(2x+3)


Question 562736: what are the factors of 6x cubed + 6x squared - 2x -2?
Answer by lwsshak3(2915) About Me  (Show Source):
You can put this solution on YOUR website!
what are the factors of 6x cubed + 6x squared - 2x -2?
6x^3+6x^2-2x-2
2x(3x^2-1)+2(3x^2-1)
(3x^2-1)(2x+2)


Question 562855: evaluate: 16 with 3/2 as an exponent












Answer by lwsshak3(2915) About Me  (Show Source):
You can put this solution on YOUR website!
evaluate: 16 with 3/2 as an exponent
Take the sqrt of 16 then cube it
16^3/2=4^3=64


Question 563811: Graph the following function using transformation. Find the vertical and horizontal asymptotes. state the domain and range
Answer by stanbon(48535) About Me  (Show Source):
You can put this solution on YOUR website!
No function posted


Question 563792: please help me solve square root equation: sqrt(-8-3x)= 4
Answer by Alan3354(21583) About Me  (Show Source):
You can put this solution on YOUR website!
please help me solve square root equation: sqrt(-8-3x)= 4
-----------
square both sides


Question 563518: v^2-2v-24
Answer by fcabanski(385) About Me  (Show Source):
You can put this solution on YOUR website!
v^2-2v-24 | Reverse FOIL...find factors of 24 that add to -2.
24 = 12*2 (NO), 8*3(no), 6*4 (4 + -6 = -2...yes)
(v-6)(v+4)| if solving for v, set it = 0
v-6=0 and thus v=6
v+4 = 0 and thus v=-4

If you need help understanding math so you can solve these problems yourself, then one on one online tutoring is the answer ($30/hr). If you need faster solutions with guaranteed detailed answers, then go with personal problem solving ($3.50-$5.50 per problem). Contact me at fcabanski@hotmail.com



Question 563052: is f(x)=x(x-1) a polynomial function explain
Answer by richard1234(4794) About Me  (Show Source):
You can put this solution on YOUR website!
Yes; if you were to expand, you obtain f(x) = x^2 - x. Alternatively, you could claim that the product of two polynomials is a polynomial.


Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795