SOLUTION: paul finishes 3/10 of a work in 6 days and then finishes the remaining work the assistance of peter in 6 days. in what time can peter alone finish the same work?

Question 988236: paul finishes 3/10 of a work in 6 days and then finishes the remaining work the assistance of peter in 6 days. in what time can peter alone finish the same work?
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Peter does one job alone in x days for a rate .
Uniform Work Rates Rule RT=J to relate rate, time, amount of work or job.

Paul's rate is job in days for a rate .

Work of Paul + work of Peter AND Paul = 1 whole job

Multiply members of the equation by to eliminate the denominators as the first steps.

x=15
RELATED QUESTIONS
A & B together can paint a room in 18 days . they work together for 8 days and then b... (answered by richwmiller,josmiceli)

Peter and Paul can do a certaion job in 3 hours. On a given day, they worked together for (answered by josmiceli)

peter and paul can do a certain job in 3 hours. on a given day, they worked together for... (answered by ankor@dixie-net.com)

Brandon and Chris together can do a piece of work in 12 days. After Brandon has worked... (answered by ankor@dixie-net.com)

Peter and Paul can do a certain job in 3 hours. On a given day, they worked together for... (answered by stanbon)

A and B can finished one piece of work in 12days. B and C finishes in 15 days. C and A... (answered by josmiceli)

i have solved that if Worker A finishes a job in 8 days and worker B finishes it in 12... (answered by josmiceli)

John can do a piece of work in 8 days and peter can do the same piece of work in 6... (answered by Fombitz)

A does 3/10 of a work in 6 days .He then calls in B and they finish the work in 7 days... (answered by ankor@dixie-net.com)