SOLUTION: A tour bus normally leaves for its destination at 5:00 p.m. for a 330 mile trip. This week however, the bus leaves at 5:30 p.m. To arrive on time, the driver drives 5 miles per hou

Question 959641: A tour bus normally leaves for its destination at 5:00 p.m. for a 330 mile trip. This week however, the bus leaves at 5:30 p.m. To arrive on time, the driver drives 5 miles per hour faster than usual. What is the bus` usual speed?
I did my best, it was not good enough
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = the usual speed in mi/hr that will result
in the bus arriving on time
Let = the time in hours that the trip takes
when the bus has speed
----------------------------------------------
Equation for a normal trip:
(1)
Equation for trip leaving at 5:30 PM
(2)
---------------------------------
(2)
(2)
and
(1)
---------------------
By substitution:
(2)
(2)
(2)
Divide both sides by
(2)
Use quadratic formula

and
(1)
(1)
(1)
The usual speed is 55 mi/hr
check:
(2)
(2)
(2)
(2)
OK

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