SOLUTION: Person A can paint the neighbor's house 5 times as fast as Person B. The year A and B worked together, it took them 7 days. How long would it take each to paint the house?
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Question 955974: Person A can paint the neighbor's house 5 times as fast as Person B. The year A and B worked together, it took them 7 days. How long would it take each to paint the house?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Person A can paint the neighbor's house 5 times as fast as Person B. The year A and B worked together, it took them 7 days. How long would it take each to paint the house?
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let x=number of days A can finish painting the house by himself
his work rate=1/x
5x=number of days B can finish painting the house by himself
his work rate=1/5x
7=number of days both A and B working together can finish painting
Their work rate=1/7
..
sum of indv. work rates=work rate working together
lcd:5x
5+1=5x/7
5x=42
x=42/5=8.4
5x=42
number of days A can finish painting the house by himself=8.4
number of days B can finish painting the house by himself=42
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