SOLUTION: Paul can paint a room two times as fast a Jamie. Working together they can paint the room in three hours. How long would it take each of them to paint the room alone?

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Question 945637: Paul can paint a room two times as fast a Jamie. Working together they can paint the room in three hours. How long would it take each of them to paint the room alone?
Found 2 solutions by TimothyLamb, MathTherapy:
Answer by TimothyLamb(4379)   (Show Source): You can put this solution on YOUR website!
x = paul's hours to paint the room alone
y = jamie's hours to paint the room alone
---
x = 2y
---
rate:
r = w/t
---
rates are additive:
1/x + 1/y = 1/3
x = 2y
1/(2y) + 1/y = 1/3
1/(2y) + 2/(2y) = 1/3
3/(2y) = 1/3
(2y) = 3*3
y = 3*3/2
y = 4.5
x = 2y
x = 9
---
answer:
x = 9
y = 4.5
---
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Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Paul can paint a room two times as fast a Jamie. Working together they can paint the room in three hours. How long would it take each of them to paint the room alone?
Paul can paint room in  hours

Jamie can paint room in 2(4.5), or  hours         

You can do the check!! 

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