SOLUTION: The sum of the areas of 2 squares is 53cm^2. The length of the side of the larger square is 5cm more than that of the smaller square. Find the length of a side of each square.

Question 904387: The sum of the areas of 2 squares is 53cm^2. The length of the side of the larger square is 5cm more than that of the smaller square. Find the length of a side of each square.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
length of side of smaller square =x
area = x^2
length of side of larger square = (x+5)
area = (x+5)^2
x^2+(x+5)^2=53
x^2+x^2+10x+25=53
2x^2+10x-28=0
2x^2+14x-4x-28=0
2x(x+7)-4(x+7)=0
(2x-4)(x+7)=0
2(x-2)(x+7)=0
x=2cm is the side of smaller square
2+5 =7cm is the length of side of larger square

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