| Solved by pluggable solver: SOLVE quadratic equation with variable |
| Quadratic equation For these solutions to exist, the discriminant First, we need to compute the discriminant Discriminant d=252 is greater than zero. That means that there are two solutions: Quadratic expression Again, the answer is: 14.9372539331938, -0.937253933193772. Here's your graph: |
| Solved by pluggable solver: SOLVE quadratic equation with variable |
| Quadratic equation For these solutions to exist, the discriminant First, we need to compute the discriminant Discriminant d=260 is greater than zero. That means that there are two solutions: Quadratic expression Again, the answer is: 15.0622577482985, -1.06225774829855. Here's your graph: |
| Solved by pluggable solver: COMPLETING THE SQUARE solver for quadratics |
| Read this lesson on completing the square by prince_abubu, if you do not know how to complete the square. Let's convert We have: Look at We are almost there. Finding the other number is simply a matter of not making too many mistakes. We need to find 'other number' such that The highlighted red part must be equal to -16 (highlighted green part). So, the equation converts to Our equation converted to a square Since the right part 65 is greater than zero, there are two solutions: , or Answer: x=15.0622577482985, -1.06225774829855. |