SOLUTION: Two machines fill cereal boxes at the same rate. After the two machines work together for 7 h, one machine breaks down. The second machine requires 14 more hours to finish filling
Algebra.Com
Question 885907: Two machines fill cereal boxes at the same rate. After the two machines work together for 7 h, one machine breaks down. The second machine requires 14 more hours to finish filling the boxes. How long would it have taken one of the machines, working alone, to fill the boxes?
Answer by josgarithmetic(39613) (Show Source): You can put this solution on YOUR website!
r = the rate of each machine in JOBS per HOUR.
The description and question imply that 1 job will be done with the two machines. The question asks for finding r.
RT=J rate, time, job
First seven hours, both machines.
= amount of job done after both machines.
Last fourteen hours, only one machine.
= amount of job done using only one machine.
The sum of those two amounts of job are 1 whole job.
-----ONE JOB IN 28 HOURS, the rate of one machine.
RELATED QUESTIONS
two machines that fill cereal boxes work at the same rate. after they work together for 7 (answered by nerdybill)
Two machines fill cereal boxes at the same rate. After the two machines work together... (answered by drk)
two machines work at the same rate. after they work together for 7 h, one machine breaks (answered by ankor@dixie-net.com)
two machines fill cereal boxes at the same time. One machine, which is filling 16-ounce... (answered by ikleyn)
suppose a factory contains two machines. there is a 19 % probability that the first... (answered by stanbon)
Machine A can do a certain job in 8 hours. machine B can do the same job in 10 hours.... (answered by stanbon)
three old machines together required 80 min to do a certain job. two new machines were... (answered by ankor@dixie-net.com)
Machine A can do a certain job in 8 hours. machine B can do the same job in 10 hours.... (answered by Boreal)
A dairy farm has two milk loading machines. The two machines started running at the same (answered by stanbon)