SOLUTION: The difference between the digits of a two-place number is 3. If the digits are reversed and the resulting number added to the original number the sum is 121. What is the original

Question 836147: The difference between the digits of a two-place number is 3. If the digits are reversed and the resulting number added to the original number the sum is 121. What is the original number?
Found 2 solutions by richwmiller, Vladdroid:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
a-b=3,
10a+b+10b+a=121,
z=10a+b
a = 7, b = 4, original z = 74
74+47=121
Answer by Vladdroid(91) (Show Source): You can put this solution on YOUR website!
a-b=3,
10a+b+10b+a=121,
z=10a+b
a = 7, b = 4, original z = 74
74+47=121
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