SOLUTION: after 4 years father's age will be 3 times as his son
and 6 years ago father's age was 7
times as his son find their present
ages ? Solution . . .
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Question 821481: after 4 years father's age will be 3 times as his son
and 6 years ago father's age was 7
times as his son find their present
ages ? Solution . . .
Found 2 solutions by TimothyLamb, balthazar612:
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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(x + 4) = 3(y + 4)
(x - 6) = 7(y - 6)
---
x + 4 = 3y + 12
x - 6 = 7y - 42
---
put the system of linear equations into standard form
---
x - 3y = 8
x - 7y = -36
---
copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
---
answer:
x= father = 41
y= son = 11
---
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---
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Answer by balthazar612(14) (Show Source): You can put this solution on YOUR website!
(x + 4) = 3(y + 4)
(x - 6) = 7(y - 6)
---
x + 4 = 3y + 12
x - 6 = 7y - 42 ---
put the system of linear equations
into standard form
---
x - 3y = 8
x - 7y = -36
Subtracting equati0n 2 from 1
4y = 44
Y = 11
Putting value of y in equation 1 we get
X-3(11) =8
X -33 =8
X= 8+33
X= 41
answer:
x= father = 41
y= son = 11
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