SOLUTION: a man has a bag of sweets he gave 1 sweet to his son then he gave 1/7 of remaining sweets to his son. Then he gave 2 sweets to his daughter then he he gave 1/7 of remaining to his

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Question 817688: a man has a bag of sweets he gave 1 sweet to his son then he gave 1/7 of remaining sweets to his son. Then he gave 2 sweets to his daughter then he he gave 1/7 of remaining to his daughter. Both child got equal numbers of sweets. What were the total sweets in the bag? Solve with explanation . .
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
a man has a bag of sweets he gave 1 sweet to his son then he gave 1/7 of remaining sweets to his son. Then he gave 2 sweets to his daughter then he he gave 1/7 of remaining to his daughter. Both child got equal numbers of sweets.
Let 'T' represent the total sweets in the bag.
Son:
Daughter:
Question states***Both child got equal numbers of sweets.

7S = 14 + T - 2 - S
8S - 12 = T
|Substitute for T
7S = 7 + 8S - 13
S = 6 (D=6) and T = 36 total sweets in the bag (8S -12)

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