SOLUTION: Peter, john and rebecca can do a job alone in 5,8, and 10 days respectively. If they all do the job together, what fraction of yhe job is done by peter?

Question 807907: Peter, john and rebecca can do a job alone in 5,8, and 10 days respectively. If they all do the job together, what fraction of yhe job is done by peter?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
First we must figure how how long it will take them to get the job done if they work together.

1/5+1/8+1/10 = 1/t

8/40+5/40+4/40 = 1/t

(8+5+4)/40 = 1/t

17/40 = 1/t

17t = 40*1

17t = 40

t = 40/17

It will take 40/17 days (roughly 2.3529 days) if they work together.

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Now divide 40/17 by 5 to figure out what fraction Peter gets done when the 3 work together.

(40/17)/5

(40/17)/(5/1)

(40/17)*(1/5)

(40*1)/(17*5)

(40)/(85)

8/17

Final Answer: Peter completes 8/17 of the job over the entire period of 40/17 = 2.3529 days when all 3 work together.
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