SOLUTION: Math problem: One slower computer, working alone takes 4 hours longer than a faster second computer. After both computers work together for one hour, the faster computer crashes.

Question 801304: Math problem: One slower computer, working alone takes 4 hours longer than a faster second computer. After both computers work together for one hour, the faster computer crashes. The slower computer continues working for another two hours competing the program. How long would it take the faster computer, working alone, to run the program ???
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Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Math problem: One slower computer, working alone takes 4 hours longer than a faster second computer. After both computers work together for one hour, the faster computer crashes. The slower computer continues working for another two hours competing the program. How long would it take the faster computer, working alone, to run the program ???
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Slower computer DATA::
time = x+4 hrs/job ; rate = 1/(x+4) job/hr
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Faster computer DATA:
time = x hrs/job ; rate = 1/x job/hr
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Work down in one hour = (1/x)+(1/x+4) = (x+4+x)/(x(x+4)) = (2x+4)/(x^2+4x)
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Equation::
1[(1/x)+1/(x+4)] + 2[1/(x+4)] = 1 job
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(1/x) + 3/(x+4) = 1
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x+4+3x = x(x+4)
x^2 +4x = 4x+4
x^2 = 4
x = 2
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How long would it take the faster computer, working alone, to run the program ???
Ans:: x = 2 hours
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Cheers,
Stan H.
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