SOLUTION: Two taps A and B can fill a tank in 3 hours and 20 minutes. When tap A alone is open, it takes 2 hours more to fill the tank, than when B alone is open. Assuming uniform flow, bow

Question 744182: Two taps A and B can fill a tank in 3 hours and 20 minutes. When tap A alone is open, it takes 2 hours more to fill the tank, than when B alone is open. Assuming uniform flow, bow long does it take for B alone to fill the tank?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
This is a job rate or task completion problem.

tap A plus tap B, rate is job per hour.
tap B, rate? Let's use h for the hours to do the job. It's not the rate, but for now it will help.
tap A, rate is job per hour.

So then how do we express the rate for tap B? This rate is job per hour.

Notice that I have been using rate as JOBS per HOUR, and not HOURS per JOB. Addition of rates for agents which work simultaneously is easier to manage this way.

rate for tap A + rate for tap B = combined rate of tab A AND tap B;
.
Solve for h.
THAT is the time for tap B to fill the tank if tap B works alone.
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