SOLUTION: Pump A can fill a tank of water in 4 hours. Pump B can fill the same tank in 6 hours. Both pumps are started at 8:00 a.m. to fill the same empty tank. An hour later, pump B breaks

Question 704592: Pump A can fill a tank of water in 4 hours. Pump B can fill the same tank in 6 hours. Both pumps are started at 8:00 a.m. to fill the same empty tank. An hour later, pump B breaks down and took one hour to repair and was restarted again. When will the tank be full? (round your answer to the nearest minute).
Answer by josgarithmetic(39623) (Show Source): You can put this solution on YOUR website!
Pump A rate = 1/4 tank per hour
Pump B rate = 1/6 tank per hour
Both pumps together rate = 1/4 + 1/6 tank per hour
Time pump A alone = 1 hour
Time pumpts together = t-1 hour
t, unknown time in hours.

Sum of jobs = The Whole Job.
(1/4)*1 amount of the job for A while worked alone
(1/4+1/6)*(t-1) amount of job for both pumps together

, the whole tank job.
.
.
hours
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