SOLUTION: A man and a boy perform a task in 2 days. They completed one-half of the task with the the first day with the man working 8 hours and the boy working 10 hours. On the next day they

Question 634365: A man and a boy perform a task in 2 days. They completed one-half of the task with the the first day with the man working 8 hours and the boy working 10 hours. On the next day they finish the task with the man working 4 hours and the boy working 15 hours. Find how many days it would take for each working alone to do the task.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A man and a boy perform a task in 2 days.
They completed one-half of the task with the the first day with the man
working 8 hours and the boy working 10 hours.
On the next day they finish the task with the man working 4 hours and the
boy working 15 hours.
Find how many days it would take for each working alone to do the task.
:
Let m = time required by the man working alone
Let b = time when boy works alone
Let the completed job = 1
:
First day
+ =
Next day
+ =
Multiply the above equation by 2, subtract the first equation
+ = 1
+ =
----------------------subtraction eliminates m, find b
0 + =
Cross multiply
b = 40 hrs, the boy alone
:
Find m
+ =
reduce the fraction
+ =
=
=
Cross mult
m = 32 hrs, the man alone
;
:
Confirm solution
+ =
+ =
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