SOLUTION: Adam, Beth, and Cory (working together) can paint a room in 6 hours less time than Adam working alone, one hour less than Beth working alone, and one-half the time needed for Cory

Question 611535: Adam, Beth, and Cory (working together) can paint a room in 6 hours less time than Adam working alone, one hour less than Beth working alone, and one-half the time needed for Cory working alone.
How long would it take Adam and Beth to paint the room working together (but without Cory)?

Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
x/a+x/b+x/c=1
a=x+6
b=x+1
c=2x
y/a+y/b=1
a=20/3
b=5/3
c=4/3
x=2/3
y=4/3
4/3 hour for Adam and Beth working together.

RELATED QUESTIONS
Joe can paint a room in 6 hours less time than Jay. If they can paint the room in 4... (answered by josgarithmetic,ikleyn)

Tom and Jerry can paint a room together in 4 hours. Working alone, Tom can paint the room (answered by edjones)

Genelle and Eljen can paint a room together in 4 hours. Working alone, Genelle can paint... (answered by checkley77)

Dave and Sandy can paint a room together in 4 hrs. Working alone, Dave can paint the room (answered by checkley79)

Beatrice and javier can paint a room in 5 hours. Working alone, javier can paint the room (answered by edjones)

Working together, Adam and Chris can reseal a driveway in 6 hours. Working alone, Adam... (answered by mananth)

One painter takes 6 hours longer to paint a room than does a second painter. Working... (answered by stanbon)

A painter can paint a room three hours less than an apprentice. Together they can pain... (answered by Mathtut,gonzo)

joe can paint a room in 6 hours less than billy. if they can paint the room in 4... (answered by checkley71)