# SOLUTION: a swimming pool is empty. at 1:00pm a hose is turned on and begins to deliver 5 gallons per minute into swimming pool. thirty minutes later a second hose is turned on and pours 7 g

Algebra ->  Algebra  -> Rate-of-work-word-problems -> SOLUTION: a swimming pool is empty. at 1:00pm a hose is turned on and begins to deliver 5 gallons per minute into swimming pool. thirty minutes later a second hose is turned on and pours 7 g      Log On

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 Click here to see ALL problems on Rate-of-work-word-problems Question 597849: a swimming pool is empty. at 1:00pm a hose is turned on and begins to deliver 5 gallons per minute into swimming pool. thirty minutes later a second hose is turned on and pours 7 gallons per minute into the pool. at what time will there be 1710 gallons of water in the pool. please explain how to work problem thanksAnswer by ankor@dixie-net.com(15652)   (Show Source): You can put this solution on YOUR website!a swimming pool is empty. at 1:00pm a hose is turned on and begins to deliver 5 gallons per minute into swimming pool. thirty minutes later a second hose is turned on and pours 7 gallons per minute into the pool. at what time will there be 1710 gallons of water in the pool. : Let t = number minutes that both hose are on (12 gal/min starting 1:30) Find the number of minutes to fill the pool : (5*30)+12t = 1710 150 + 12t = 1710 12t = 1710 - 150 12t = 1560 t = 1560/12 t = 130 minutes from 1:30 pm therefore 1:30 + 2:10 = 3:40 pm will have 1710 gal in the pool