# SOLUTION: A ball is thrown straight upward with an initial velocity of 52ft/sec. Its height above the ground after t seconds is given by the formula h(t)=16t^2+52t. At what time will the bal

Algebra ->  Algebra  -> Rate-of-work-word-problems -> SOLUTION: A ball is thrown straight upward with an initial velocity of 52ft/sec. Its height above the ground after t seconds is given by the formula h(t)=16t^2+52t. At what time will the bal      Log On

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 Click here to see ALL problems on Rate-of-work-word-problems Question 595649: A ball is thrown straight upward with an initial velocity of 52ft/sec. Its height above the ground after t seconds is given by the formula h(t)=16t^2+52t. At what time will the ball hit the ground? (in seconds)Answer by nerdybill(7012)   (Show Source): You can put this solution on YOUR website! A ball is thrown straight upward with an initial velocity of 52ft/sec. Its height above the ground after t seconds is given by the formula h(t)=-16t^2+52t. At what time will the ball hit the ground? (in seconds) . Since height is zero when it hits the ground, set h(t) to zero and solve for t: h(t)=16t^2+52t 0=-16t^2+52t 0=16t^2-52t 0=t(16t-52) t = {0, 52/16} t = {0, 3.25} answer: 3.25 seconds