SOLUTION: person a can paint the neighbors house 6 times as fast as person b. the year a and b worked together, it took them 8 days. how long would it take each to paint the house

Algebra.Com
Question 521551: person a can paint the neighbors house 6 times as fast as person b. the year a and b worked together, it took them 8 days. how long would it take each to paint the house
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
8/a+8/b=1
a=b/6
48/6b+8/6b=1
56/6b=1
56=6b
56/6=b
28/3=b
a=28/3*6
a=14/9


RELATED QUESTIONS

Person A can paint the neighbors house 2 times as fast as person B. The year A and B... (answered by josgarithmetic,ankor@dixie-net.com)
Person A can paint the neighbors house six times as fast as a person b, the year A and B (answered by josgarithmetic)
Person A can paint the neighbors house 2 times as fast as person B. The year A and B... (answered by ikleyn,greenestamps)
If Person A can pain the house 6 times as fast as person B. The year A and B worked... (answered by ankor@dixie-net.com)
Person A can paint the neighbor's house 5 times as fast as Person B. The year A and B... (answered by ankor@dixie-net.com)
Person A can paint the neighbor's house 5 times as fast as Person B. The year A and B... (answered by lwsshak3)
Person A can paint the neighbor's house 2 times as fast as Person B. The year A and B... (answered by richwmiller)
Person A can paint the​ neighbor's house 4 times as fast as Person B. The year A... (answered by stanbon)
Person A can paint the neighbor's house 5 times as fast as Person B. The year A and B... (answered by josmiceli)