it takes Tom and John 2 hours to do a certain job,it takes tom and harry 3 hours to do the same job and it takes john and harry 4 hours to do the same job. how long would it take tom, john and harry to do the job if all 3 worked together?
Make the chart below. The number of jobs done in all cases is 1.
Let t = Tom's hours to do the 1 job alone
Let j = John's hours to do the 1 job alone
Let h = Harry's hours to do the 1 job alone
Let x = the answer, the number of hours it would take if
all three worked together.
number of
jobs done time in hrs rate in jobs/hr
Tom only 1 t
John only 1 j
Harry only 1 h
Tom & John 1 2
Tom & Harry 1 3
John & Harry 1 4
Tom, John & Harry 1 x
Now we fill in all the rates in jobs/hour by dividing the number of
jobs by the number of hours:
number of
jobs done time in hrs rate in jobs/hr
Tom only 1 t 1/t
John only 1 j 1/j
Harry only 1 h 1/h
Tom & John 1 2 1/2
Tom & Harry 1 3 1/3
John & Harry 1 4 1/4
Tom, John & Harry 1 x 1/x
Tom's rate + John's rate = Tom & John's rate together
1/t + 1/j = 1/2
Tom's rate + Harry's rate = Tom & Harry's rate together
1/t + 1/h = 1/3
John's rate + Harry's rate = John & Harry's rate together
1/j + 1/h = 1/4
So we have this system of equations:
1/t + 1/j = 1/2
1/t + 1/h = 1/3
1/j + 1/h = 1/4
Let A = 1/t, B = 1/j, C = 1/h
A + B = 1/2
A + C = 1/3
B + C = 1/4
Clear of fractions:
2A + 2B = 1
3A + 3C = 1
4B + 4C = 1
Line up like terms:
2A + 2B = 1
3A + 3C = 1
4B + 4C = 1
Can you can solve that by elimination?
If you don't know how, post again asking
how to solve that system by elimination.
answers:
A = 7/24, B = 5/24, C = 1/24
A = 1/t = 7/24 jobs/hour is Tom's rate
B = 1/j = 5/24 jobs/hour is John's rate
C = 1/h = 1/24 jobs/hour is Harry's rate
Now we use the equation:
Tom's rate + John's rate + Harry's rate = Tom, John & Harry's combined rate
7/24 + 5/24 + 1/24 = 1/x
Multiply through by LCD of 24x
7x + 5x + x = 24
13x = 24
x = 24/13
x = 1 11/13 hours
Edwin