# SOLUTION: an object that is projected straight downward with an initial velocity of v per second travels a distance s = vt + 9t^2, where t=time in seconds. if dan is standing on a balcony 17

Algebra ->  Algebra  -> Rate-of-work-word-problems -> SOLUTION: an object that is projected straight downward with an initial velocity of v per second travels a distance s = vt + 9t^2, where t=time in seconds. if dan is standing on a balcony 17      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Word Problems: Rate of work, PAINTING, Pool Filling Solvers Lessons Answers archive Quiz In Depth

 Question 452889: an object that is projected straight downward with an initial velocity of v per second travels a distance s = vt + 9t^2, where t=time in seconds. if dan is standing on a balcony 176 feet above the ground and throws a penny straight downward with an intial velocity of 8 feet per second, in how many seconds will it reach the ground?Answer by lwsshak3(6490)   (Show Source): You can put this solution on YOUR website!an object that is projected straight downward with an initial velocity of v per second travels a distance s = vt + 9t^2, where t=time in seconds. if dan is standing on a balcony 176 feet above the ground and throws a penny straight downward with an intial velocity of 8 feet per second, in how many seconds will it reach the ground? .. When the object reaches the ground it will have traveled 176 feet 176=8t+9t^2 9t^2+8t-176=0 solve by following quadratic formula .. .. a=9, b=8, c=-176 t=[-8ħsqrt(8^2-4*9*-176)]/2*9 t=[-8ħsqrt(6400)]/18 t=(-8ħ80)/18 t=72/18=4 sec or t=-88/18=-4.88..(reject, time≥0) ans: The object wll reach the ground in 4 seconds.