SOLUTION: Joan is traveling on a bike path at 20 miles per hour. Thirty minutes after she started, Jack follows her at 25 miles per hour. How long does it take Jack to catch up with her?

Question 423210: Joan is traveling on a bike path at 20 miles per hour. Thirty minutes after she started, Jack follows her at 25 miles per hour. How long does it take Jack to catch up with her?
(by me)-> please show equation construction,
I'm left-handed so I'm a bit of a spatial learner, need to see to fully understand.
Found 2 solutions by Alan3354, lwsshak3:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Joan is traveling on a bike path at 20 miles per hour. Thirty minutes after she started, Jack follows her at 25 miles per hour. How long does it take Jack to catch up with her?
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In 30 mins, Joan is 10 miles away (20 mph * 0.5 hr)
Jack gains on her at 5 mph (25 - 20)
10 miles/5 mph = 2 hours

Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Joan is traveling on a bike path at 20 miles per hour. Thirty minutes after she started, Jack follows her at 25 miles per hour. How long does it take Jack to catch up with her?
..
When Jack catches up with Joan they both will have traveled the same distance.
let x=hours Jack will have traveled to catch up with Joan.
x+1/2=hours Joan will have traveled
Distance=speed*travel time
Distance Jack traveled=25x
Distance Joan traveled=20(x+1/2)
25x=20(x+1/2)
25x=20x+10
5x=10
x=2 hours
ans:
It will take Jack 2 hours to catch up with Joan.
note: they both traveled 50 miles

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