# SOLUTION: When 2 pipes are open, a tank is filled in 12 minutes. On one occasion, the first pipe was open for 10 minutes. Then the second pipe was opened and together they finished in 6 mi

Algebra ->  Algebra  -> Rate-of-work-word-problems -> SOLUTION: When 2 pipes are open, a tank is filled in 12 minutes. On one occasion, the first pipe was open for 10 minutes. Then the second pipe was opened and together they finished in 6 mi      Log On

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 Question 417815: When 2 pipes are open, a tank is filled in 12 minutes. On one occasion, the first pipe was open for 10 minutes. Then the second pipe was opened and together they finished in 6 minutes. How long would it take each pipe by itself to fill the tank? Heeeeelp.Answer by lwsshak3(6461)   (Show Source): You can put this solution on YOUR website!When 2 pipes are open, a tank is filled in 12 minutes. On one occasion, the first pipe was open for 10 minutes. Then the second pipe was opened and together they finished in 6 minutes. How long would it take each pipe by itself to fill the tank .. let x=minutes first pipe would take to fill the tank alone. 1/x=minute rate of first pipe let y=minutes second pipe would take to fill the tank alone. 1/y=minute rate of second pipe 1/12=given minute rate when working together sum of individual rates = rate when working together first condition, 1/x+1/y=1/12 1/y=1/12-1/x .. second condition first pipe worked for 16 minutes with second pipe to finish the job second pipe worked for 6 minutes with first pipe to finish the job (1/x)*16+(1/y)*6=100%=1 (1/x)*16+(1/12-1/x)*6=1 16/x+6/12-6/x=1 10/x+1/2=1 10/x=1/2 x/10=2 x=20 minutes 1/y=1/12-1/x 1/y=1/12-1/20 LCD=60 60/y=5-3=2 y=30 minutes ans: It would take the first pipe 20 minutes to fill the tank by itself. It would take the second pipe 30 minutes to fill the tank by itself.