SOLUTION: An oil tanker can be emptied by the main pump in 4 hours. An auxiliary pump can empty the tanker in 7 hours. If the main pump is started at 7 pm, when should the auxiliary pump be
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Question 413815: An oil tanker can be emptied by the main pump in 4 hours. An auxiliary pump can empty the tanker in 7 hours. If the main pump is started at 7 pm, when should the auxiliary pump be started so that the tanker is emptied by 10 pm?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The tanker is to be emptied in 2 stages in 3 hrs.
Let = hours that main pump alone is working
Amount pumped by main pump =
(1)
That is: (1 tank)/(4 hrs) x (t hrs)
The auxilliary pump + main pump will then pump out:
(2)
If I add (1) and (2), I should get (1 tank pumped)
Multiply both sides by
hrs
So, the main pump runs alone for 1 hr 15 min. That means
the auxilliary pump comes on at 8:15
check answer:
OK
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