SOLUTION: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together t
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Question 362533: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks?
Found 2 solutions by josmiceli, HasanSahin:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let 20 drinks = task
Let = the time it takes them working
together to mix 20 drinks or task
Steven's rate of mixing =
Sue's rate of mixing =
Jack's rate of mixing =
-----------------
Working together, their combined rate is:
Multiply both sides by
min
Answer by HasanSahin(52) (Show Source): You can put this solution on YOUR website!
First we have to compute how many drinks they can mix in a certain time..
Steven can mix 4 drinks/min,Sue can mix 2 drinks/min, and Jack can mix (4/3)drinks/min
After then we will compute how much time it will take for 20 drinks such that;
[4dr/min + 2dr/min + (4/3)dr/min]*t = 20 dr
[(22/3)dr/min]*t = 20 dr
So that t=30/11 min
RF.
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