# SOLUTION: After riding at a steady speed for 40 miles, a bicyclist had a flat tire and walked 5 miles to a repair shop. The cyclist rate was 4 times faster than the walking rate. If the time

Algebra ->  Algebra  -> Rate-of-work-word-problems -> SOLUTION: After riding at a steady speed for 40 miles, a bicyclist had a flat tire and walked 5 miles to a repair shop. The cyclist rate was 4 times faster than the walking rate. If the time      Log On

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 Question 297096: After riding at a steady speed for 40 miles, a bicyclist had a flat tire and walked 5 miles to a repair shop. The cyclist rate was 4 times faster than the walking rate. If the time spend on the cycling and walking was 5 hours, at what rate was the cyclist riding?Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!After riding at a steady speed for 40 miles, a bicyclist had a flat tire and walked 5 miles to a repair shop. The cyclist rate was 4 times faster than the walking rate. If the time spend on the cycling and walking was 5 hours, at what rate was the cyclist riding? let walking rate x cycling rate will be 4x time taken to ride 40 miles = 40/4x time taken to walk 5 miles = 5/x the total time taken was 5 hours 40/4x + 5/x = 5 40+20 =20x 60=20x x=3 mph the walking rate riding rate = 4x= 12 mph