SOLUTION: Question 1: Sarah takes 6 hours to complete a job which mary could do in half the time. how many hours would it take to complete the job if they both worked together?
Question 2
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Question 2
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Question 294082: Question 1: Sarah takes 6 hours to complete a job which mary could do in half the time. how many hours would it take to complete the job if they both worked together?
Question 2: The time it takes to empty a tank varies inversely as the rate of pumping. if a pump working at 600 kl/min takes 45 minutes to empty a tank. how long would it take to empty the same tank if the rate was increased to 1000 kl/min?
Any help will be greatly appreciated. thx you very much in advance. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Question 1: Sarah takes 6 hours to complete a job which mary could do in half the time.
how many hours would it take to complete the job if they both worked together?
:
From the given information we know Mary takes 3 hrs to complete the job
:
Let t = time required when they work together
:
Let the competed job = 1
: + = 1
Multiply by 6, results:
t + 2t = 6
3t = 6
t = 2 hrs working together
:
:
Question 2: The time it takes to empty a tank varies inversely as the rate of pumping.
if a pump working at 600 kl/min takes 45 minutes to empty a tank.
how long would it take to empty the same tank if the rate was increased to 1000 kl/min?
:
Let x = time required when pumping 1000kl/min
:
An inverse ratio equation =
Cross multiply
1000x = 600 * 45
x =
x = 27 min when it pumps at 1000kl/min
